99爱在线视频这里只有精品_窝窝午夜看片成人精品_日韩精品久久久毛片一区二区_亚洲一区二区久久

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

代寫SI 100B、代做Python設計程序
代寫SI 100B、代做Python設計程序

時間:2024-11-01  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



SI 100B Programming Assignment 2
SI 100B TA Team
October 23, 2024
1
Notice
• This homework is due 10:00 AM October 30, Wednesday, please start early.
• The problems should be solved individually. You should submit solutions for all problems to the online
judge (OJ) system, which will give a score for each submission automatically.
• You may discuss course material, programming languages, general techniques, and share test cases with
others.
• You’re encouraged to ask any question about problem description, environment setup, error informa tion, grammar, functions, methods etc., or post general ideas at Piazza. It can help others too!
• However, you may NOT read, possess, copy, or submit any part of other’s solution. You may not ask
others to directly debug your program or provide specific lines of solution. You should not access an other person’s account. Also, do not offer such help, and protect your account and code. Giving or
receiving inappropriate help is plagiarism, an infringement of academic integrity.
• You are not allowed to write your solution directly by or based on code generated by AI tools.
• Good luck and have fun!
2
1 UNFORTUNATE STOCKHOLDER
1 Unfortunate Stockholder
“I really hate green,” the poor man sighed, looking down, and found his beloved Alexandra Nikolaevna
Petrovskaya lying on the floor, stiff and cold. With her gone, his nearly hairless head now has one less hair.
A month ago, he was still a rich man, with positive daily profit from his investments. However, without
him noticing, some of his stocks had been falling for several days, and then suddenly hit the lower limit.
Quicker than he could take any actions, his other stocks also began falling.
Because he had so many stocks, he only checked the total profit every day.“Oh God! How I wish I had a
tool that can tell me the details of my stocks!”
1.1 Task
As it happens, you know how to use python, and you will kindly fulfill his wish by writing a python
program to give the details of his stocks. You will be given a list of numbers, representing the profit of his
stocks, and a series of queries. For each query, you should perform the corresponding operation and print the
result.
1.2 Input/Output Specification
1.2.1 Input
The first line contains a string of float numbers, representing the profit of the stocks.
The second line contains a single positive integer n, indicating the number of queries.
Each of the following n lines contains a query, with details shown in the Table below. All queries will be
given in one of the formats
• query, operation
• query, operation, start_index, end_index, step
query, operation, start_index, end_index, step means querying on the profit of a subset of the stocks ob tained by performing slicing operation. It is guaranteed that start_index, end_index and step are all integers.
If the subset of the stocks to be queried is empty, print Querying on empty list! (with a single space
at the end of the output) and do nothing else.
1.2.2 Output
n lines, each line the result of the query.
3
1.2 Input/Output Specification 1 UNFORTUNATE STOCKHOLDER
Query Operation Example Input Result
find
min find, min the min profit amongst all stocks
find, min, 1, 3, 1 the min profit amongst the sliced subset of stocks
max
find, max the max profit amongst all stocks
find, max, 5, 9, 2 the max profit amongst the sliced subset of stocks
index
a single index, 10 the profit of the stock with index i
positive integer i
slice index, slice, 2, 3, 1 the list of profits of the sliced subset of stocks
compute
avg
compute, avg the average profit of all stocks
compute, avg, 5, 12, 3 the average profit of the sliced subset of stocks
all compute, all the total profit of all stocks
compute, all, 6, 3, 2 the total profit of the sliced subset of stocks
reorder
asc
reorder, asc the reordered list of profits
of all stocks in ascending order
reorder, asc, 7, 30, 1 the list of profits with the profits of the
sliced stocks reordered in ascending order
desc
reorder, desc the reordered list of profits
of all stocks in descending order
reorder, desc, 3, 4, 2 the list of profits with the profits of the
sliced stocks reordered in descending order
rev
reorder, rev the reordered list of profits
of all stocks in reverse order
reorder, rev, 9, 3, 3 the list of profits with the profits of the
sliced stocks reordered in reverse order
1.2.3 Example
1. Input
1 4 5 3 4 2 5 −2 −3 0 2
5
find, min
find, max, 0, 3, 1
compute, avg, 2, 12, 1
reorder, rev
reorder, asc, 1, 6, 1
Output
−3.0
5.0
1.7777777777777777
[2.0, 0.0, −3.0, −2.0, 5.0, 2.0, 4.0, 3.0, 5.0, 4.0, 1.0]
[2.0, −3.0, −2.0, 0.0, 2.0, 5.0, 4.0, 3.0, 5.0, 4.0, 1.0]
4
1.3 Hint 2 AVERAGE RUNNING SPEED
2. Input
1 2 3 4 5 6
5
index, 5
index, slice, 1, 4, 2
compute, all
reorder, desc, 6, 3, −1
find, max, 2, 4, 1
Output
6.0
[2.0, 4.0]
21.0
[1.0, 2.0, 3.0, 4.0, 5.0, 6.0]
4.0
1.3 Hint
After each reorder query, the list is reordered (i.e., it is mutated), as shown in the examples.
2 Average Running Speed
As part of promoting a healthy lifestyle, the university has introduced a running App. The App generates
data points consecutively containing the student’s positions and timestamps during their running sessions.
The App helps generate useful statistics, such as distance covered and average speed. And students can freely
select specific data points for customized analysis.
2.1 Task
You are tasked with writing a program to process data points of a running session and then evaluate
a runner’s performance. Your program receives n data points at the beginning. The i-th data point Pi =
(xi
, yi
, ti), where xi and yi are the runner’s 2D coordinates, ti
is the timestamp measured in seconds. For
simplicity, we assume that runners travels along a straight path between two adjacent points, so the distance
between two adjacent data points is estimated using the Euclidean distance formula:
D(Pk, Pk−1) = √
(xk−xk−1)
2 + (yk−yk−1)
2
5
2.2 Input/Output Specification 2 AVERAGE RUNNING SPEED
Firstly, you need to estimate the average speed V of the entire session, note that the session starts at P0 and
ends at Pn−1:
V =
∑n
k=1 D(Pk, Pk−1)
tn−1 − t0
Then the runner will freely select m subsections, with the i-th subsection represented by the indices of two
data points, starti and endi
. And the runner wants to know what the average running speed is for each
subsection, i.e., the average speed V i running through Pstarti
, Pstarti+1, . . . , Pendi−1, Pendi
2.2 Input/Output Specification
2.2.1 Input
The first line contains a single integer n, the number of data points in the running session (2 ≤ n ≤ 100).
The next n lines of data points contains three integers each: xi
, yi
, ti
, where xi and yi
is the runner’s
coordinate (−100 ≤ xi
, yi ≤ 100), ti
is the timestamp at the i-th data point (0 ≤ t0 < t1 < t2 . . . < tn−1 ≤
103
).
The next line contains a single integer m, the number of the selected subsections.
The next m lines contains two values each: starti
, endi
, which represents the indices of start point and
end point of the i-th subsection (0 ≤ starti < endi < n).
2.2.2 Output
The first line is the average speed V of the entire session. And the next m lines: each line contains the
average speed V i for the i-th subsection. V and V i should be formatted to three decimal places.
2.2.3 Example
1. Input
4
1 2 1
** 5
4 8 12
2 1 18
1
1 3
Output
1.129
1.009
6
3 I OR E
2. Input
5
48 8 2
−83 −85 4
60 14 11
−37 −37 19
−15 −31 20
2
3 4
0 2
Output
25.943
22.804
37.176
3 I or E
Myers–Briggs Type Indicator (MBTI) is a assessment particularly popular in social occasions. There is
one dimension: energy orientation, which is divided into introversion and extraversion—— extraverted person
obtains energy from social interactions, while introverted person obtains energy from self-reflection.
However, a person’s energy orientation is not fixed. For example, a person who is initially classified as
introverted may turn out to be extraverted under some circumstances.
3.1 Task
In this scenario, a meeting consists of participants of three initial orientations: “E”, “I”, and “i”. You are
given a seating arrangement represented as an n × m matrix where n is the number of rows. And each seat
position indicates the energy orientation of a participant (E, I, or i). Your task is to print out the final energy
orientation in matrix format.
Participants will sit one by one, from the first row to the last row, and within each row, from left to right.
During this process, if an “i” participant is surrounded by introverted person (either “I” or “i”), they will change
their orientation to extraverted, denoted as “e”. A participant is considered surrounded by introverted person
if all their adjacent neighbors (up, down, left, right) are either I or i. If the participant is on the boundary
or corner, only the existing neighbors are considered.
There is a special case when the last participant seated: first update the previously seated participants
before considering the last one, in order to avoid potential conflicts.
7
3.2 Input/Output Specification 3 I OR E
3.2 Input/Output Specification
3.2.1 Input
The first line contains two integers n and m, representing the dimensions of the seating matrix (n × m),
(2 ≤ n, m ≤ 50). The following n lines each contain m separated characters c ∈ {E, I, i}, indicating the
energy orientation of the participants in each seat.
3.2.2 Output
You should output n lines, each containing one list, representing the final energy orientation of the par ticipants after they are seated in order.
3.2.3 Example
1. Input
3 4
E I i I
i I i i
i I I i
Output
['E', 'I', 'e', 'I']
['i', 'I', 'i', 'e']
['e', 'I', 'I', 'i']
Case Explanation: for convenience, we use a tuple (i, j) (count from 1), to represent the seat located
at the i-th row and j-th column. The orientation of the participant changed in the following order:
(a) (1, 3) changed when (2, 3) seated.
(b) (3, 1) changed when (3, 2) seated.
(c) (2, 3) changed when (3, 3) seated. Remember to update the previously seated participants before
the last one.
2. Input
5 5
E I i I E
i I i I I
I i I i E
I I i i I
i I I I i
8
4 TURTLE BLIND BOXES
Output
['E', 'I', 'e', 'I', 'E']
['i', 'I', 'i', 'I', 'I']
['I', 'e', 'I', 'i', 'E']
['I', 'I', 'e', 'i', 'I']
['e', 'I', 'I', 'I', 'e']
Case Explanation: The orientation of the participant changed in the following order:
(a) (1, 3) changed when (2, 3) seated.
(b) (3, 2) changed when (4, 2) seated.
(c) (5, 1) changed when (5, 2) seated.
(d) (4, 3) changed when (5, 3) seated.
(e) (5, 5) changed when (5, 5) seated.
4 Turtle Blind Boxes
Blind box opening games have become increasingly popular on platforms such as TikTok. In this assign ment, you will simulate a blind box opening game where the contents are small glass turtles of different colors
and patterns. The objective is to simulate the entire process of purchasing, opening, and placing these turtles
in a grid, following specific rules to either eliminate or reward the player with additional blind boxes based
on turtle combinations.
Each turtle has a color and a pattern, with the following possibilities:
• Colors: Red, Orange, Yellow, Green, Blue
• Patterns: Patterned, Unpatterned
The game uses a 3x3 grid to display the turtles, and there are several conditions that trigger rewards or elimi nations during the gameplay.
4.1 Task
You are required to write a Python program that simulates this turtle blind box game. The game follows
specific rules for rewarding the player with extra blind boxes or eliminating turtles from the grid. The detailed
task breakdown is as follows:
1. Get Blind Box Content: Each blind box contains one glass turtle with a randomly generated color and
pattern combination.
9
4.2 Input/Output Specification 4 TURTLE BLIND BOXES
2. Wish Mechanism: The player can wish for a specific color and pattern combination. If a turtle match ing the player’s wish is opened, they are immediately rewarded with one additional blind box.
3. Grid Filling: Each turtle is placed in a 3x3 grid (like a Tic-Tac-Toe board), and the turtles are placed
in the grid according to the numbered order of the cells (1 to 9), where 1 is the top-left and 9 is the
bottom-right.
4. Elimination and Reward Rules: After the grid is filled or all blind boxes have been opened, perform
the following operations in the specified order:
(a) All Different: If the grid is full and all turtles in the grid are different, remove all turtles and
reward the player with 5 additional blind boxes.
(b) Three of a Kind: If three identical turtles align horizontally, vertically, or diagonally, reward the
player with 5 additional blind boxes. The turtles remain in the grid. If there are multiple triples at
the same time, each triple should be given 5 new blind boxes.
(c) Pairs: If two identical turtles are found, they are eliminated from the grid, and the player is
rewarded with 1 additional blind box per pair. Turtles in cells with smaller numbers (lower numbered positions in the grid) are prioritized for removal.
5. End Condition: The game ends when no more blind boxes are available, and no turtles can be elimi nated.
4.2 Input/Output Specification
4.2.1 Input
The program will accept the following four lines of input:
1. The number of initial blind boxes purchased.
2. The player’s wish for a specific turtle’s color and pattern. Use two letters separated by a space to repre sent turtle.
3. A list of randomly generated turtles, with two lines:
• The first line represents the colors of the turtles, using the first letter of each color: R (Red), O
(Orange), Y (Yellow), G (Green), B (Blue).
• The second line represents the patterns of the turtles, using the first letter of each pattern: P
(Patterned), U (Unpatterned).
10
4.2 Input/Output Specification 4 TURTLE BLIND BOXES
The color and pattern of the i-th turtle are represented by the i-th letter in the third and fourth rows. The
number of turtles provided is undetermined, but it’s guaranteed to be larger than the number required for the
simulation.
4.2.2 Output
At the end of the game, output the list of eliminated turtles in the order they were removed from the grid.
Turtles should be represented by tuples of (color, pattern). At the end of the game, the remaining turtles in the
grid should also be eliminated in the order of the numbers in the nine-square grid. You can use print(list)
directly.
4.2.3 Example
1. Input
10
R U
YOBOOBRGOGYBYRYYGBO
UUUUPUUPPPUUUUPUUPU
Output
[('O', 'U'), ('O', 'U'), ('B', 'U'), ('B', 'U'), ('O', 'P'), ('O', 'P'),
('Y', 'U'), ('Y', 'U'), ('G', 'P'), ('G', 'P'), ('R', 'U'), ('R', 'U'),
('Y', 'U'), ('Y', 'U'), ('O', 'U'), ('G', 'U'), ('B', 'P'), ('B', 'U'),
('Y', 'P')]
2. Input
12
R P
RYOYYYROBYRBGGYOGBBYOBYBRYGOROROYGORGOY
PUPPPPUUPPPUUUPPPUPUPPUUPUPUPPUUUUPUUPU
Output
[('Y', 'P'), ('Y', 'P'), ('R', 'P'), ('R', 'P'), ('Y', 'P'), ('Y', 'P'),
('G', 'U'), ('G', 'U'), ('O', 'P'), ('O', 'P'), ('B', 'U'), ('B', 'U'),
('B', 'P'), ('B', 'P'), ('Y', 'U'), ('Y', 'U'), ('B', 'U'), ('R', 'P'),
('O', 'P'), ('B', 'P'), ('G', 'P'), ('Y', 'P'), ('R', 'U'), ('O', 'U'),
('Y', 'U'), ('Y', 'U'), ('Y', 'U'), ('O', 'U'), ('O', 'U'), ('O', 'P'),
('O', 'P'), ('R', 'U'), ('R', 'U'), ('G', 'U'), ('G', 'U'), ('Y', 'U'),
('G', 'P'), ('O', 'P'), ('R', 'P')]
11
4.3 Hint 4 TURTLE BLIND BOXES
4.3 Hint
• Randomly generate test data for debugging: To test your implementation, you can generate random
turtle combinations and simulate different scenarios (e.g., many identical turtles, all different turtles) to
check if the elimination rules are applied correctly.
• Pay attention to the execution order: Make sure that the elimination rules (e.g., three of a kind,
pairs, all different) are applied in the correct sequence. Follow the order of operations as specified in
the task to ensure accurate simulation.
• Modular design: During the implementation process, keep your code modular by breaking down dif ferent functionalities (e.g., adding turtles to the grid, checking for three of a kind, eliminating pairs) into
separate functions. This will make your code easier to understand, debug, and extend.
12

請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp




 

掃一掃在手機打開當前頁
  • 上一篇:CSCI 201代做、代寫c/c++,Python編程
  • 下一篇:CE243編程代寫、代做C/C++程序語言
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
    合肥機場巴士2號線
    合肥機場巴士2號線
    合肥機場巴士1號線
    合肥機場巴士1號線
  • 短信驗證碼 豆包 幣安下載 AI生圖 目錄網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    99爱在线视频这里只有精品_窝窝午夜看片成人精品_日韩精品久久久毛片一区二区_亚洲一区二区久久

          9000px;">

                国产在线一区观看| 亚洲一区欧美一区| 91精品国产高清一区二区三区蜜臀| 91蜜桃网址入口| 日韩精品一区二区三区中文精品| 国产精品网友自拍| 美女视频一区二区| 欧美日韩免费在线视频| 中文字幕日韩av资源站| 精品无人码麻豆乱码1区2区| 日韩二区三区在线观看| 欧美精品国产精品| 麻豆国产欧美日韩综合精品二区| 色婷婷精品久久二区二区蜜臀av| 日韩精品一区二区三区在线| 看电影不卡的网站| 日韩一区二区在线观看| 日韩成人午夜精品| 久久久精品免费网站| 国产99久久久久| 亚洲人精品一区| 91黄视频在线观看| 捆绑调教一区二区三区| 久久色中文字幕| 色悠悠亚洲一区二区| 日韩高清一区二区| 国产精品美女久久久久aⅴ国产馆| 极品少妇xxxx精品少妇| 中文字幕的久久| 中文字幕精品三区| 在线不卡a资源高清| 国产欧美日韩另类视频免费观看| 国内精品国产成人| 亚洲黄色免费网站| 色www精品视频在线观看| 亚洲韩国精品一区| 欧美一二三四区在线| 成人免费视频视频在线观看免费| 亚洲自拍都市欧美小说| 久久久精品日韩欧美| 91精品国产综合久久久久久久久久| 精品一二三四区| 婷婷开心激情综合| 一区二区欧美精品| 亚洲三级电影全部在线观看高清| 欧美一级理论片| 欧美精品精品一区| 91精品在线麻豆| 欧美一区二区三级| 欧美色老头old∨ideo| jlzzjlzz欧美大全| 国产成人精品三级| 国产精品小仙女| 国产福利精品导航| 国产一区亚洲一区| 国产精品一二三四五| 久久se精品一区二区| 国产一区二区毛片| 国产在线麻豆精品观看| 国产一区二区免费在线| 一本到不卡精品视频在线观看| 色婷婷狠狠综合| 欧美视频精品在线观看| 91精品国产免费| 中文字幕 久热精品 视频在线| 亚洲国产成人一区二区三区| 亚洲色图视频网站| 亚洲6080在线| 国产成人综合自拍| 欧美性色黄大片手机版| 久久免费国产精品| 亚洲风情在线资源站| 成人免费高清视频| 91精品国产一区二区三区香蕉| 欧美电影免费观看完整版| 亚洲欧美另类久久久精品| 国产美女精品一区二区三区| 欧美日韩一区不卡| 一二三区精品视频| www.亚洲国产| 国产欧美一区二区三区在线看蜜臀 | 亚洲三级理论片| 精品一区二区三区在线播放 | 久久久www免费人成精品| 亚洲高清不卡在线| 日本韩国精品一区二区在线观看| 日本一区二区三区国色天香| 国产一区二区三区四| 国产精品久久久久影院色老大| 黄色资源网久久资源365| 日韩欧美国产一区二区三区| 亚洲欧美日韩一区| 欧美精品在线一区二区三区| 免费成人结看片| 久久久久青草大香线综合精品| 国产盗摄一区二区| 亚洲精品欧美综合四区| 精品日韩一区二区三区免费视频| 九色|91porny| 亚洲黄色小视频| 久久日韩精品一区二区五区| 国产成人在线免费| 亚洲图片欧美综合| 成人一级片网址| 亚洲国产高清aⅴ视频| 欧美午夜精品久久久久久超碰| 婷婷成人激情在线网| 久久精品视频一区二区| 欧美日韩在线电影| 91欧美激情一区二区三区成人| 日本va欧美va瓶| 亚洲精品免费电影| 精品久久人人做人人爽| 日本久久电影网| 国产在线乱码一区二区三区| 亚洲一二三四区| 亚洲欧美一区二区不卡| 国产嫩草影院久久久久| 欧美一级久久久久久久大片| 在线亚洲+欧美+日本专区| www.欧美精品一二区| 国产精品乡下勾搭老头1| 久久精品国产亚洲a| 久久99这里只有精品| 国产综合色精品一区二区三区| 日本大胆欧美人术艺术动态| 麻豆久久久久久久| 国产资源在线一区| 国产精品一区二区果冻传媒| 国产美女主播视频一区| 国产在线不卡一区| 91小视频免费观看| 欧美日韩国产系列| 91精品国产综合久久国产大片 | 懂色av中文一区二区三区| 国产毛片一区二区| 99re成人在线| 精品少妇一区二区三区| 国产偷国产偷精品高清尤物| 亚洲自拍偷拍av| 国产一区二区女| 欧美日韩精品电影| 国产亚洲欧美日韩俺去了| 一级精品视频在线观看宜春院 | 日韩欧美电影一二三| 91精品蜜臀在线一区尤物| 国产精品私房写真福利视频| 日韩电影一二三区| 在线亚洲人成电影网站色www| 欧美一区二区三区的| 亚洲综合色区另类av| 国产成人免费在线观看不卡| 欧美这里有精品| 亚洲欧洲av在线| 高清不卡一区二区| 日本一二三不卡| 国产精品中文有码| 久久久久综合网| 麻豆久久久久久久| 精品福利av导航| 国产一二精品视频| 国产精品麻豆视频| 国产v综合v亚洲欧| 国产精品嫩草99a| 91麻豆swag| 日日夜夜精品视频天天综合网| 在线观看亚洲一区| 亚洲香蕉伊在人在线观| 欧美久久久一区| 国产很黄免费观看久久| 日本一区二区三区国色天香 | 高清不卡一区二区在线| 亚洲欧美日韩系列| 9191精品国产综合久久久久久| 日本伊人色综合网| 国产欧美日韩一区二区三区在线观看| 丁香天五香天堂综合| 亚洲一区二区三区四区在线免费观看| 欧美视频中文字幕| 国产在线不卡视频| 亚洲成人777| 亚洲欧美激情插| 中文字幕乱码日本亚洲一区二区| 欧美精品视频www在线观看| 成人永久免费视频| 激情综合色丁香一区二区| 一区二区国产盗摄色噜噜| 久久蜜臀中文字幕| 欧美一区国产二区| 91丝袜美女网| 99久久婷婷国产| 不卡影院免费观看| 成人黄动漫网站免费app| 久久精品av麻豆的观看方式| 亚洲一区精品在线| 亚洲欧美日韩久久精品| 综合久久久久久| 亚洲制服丝袜av| 亚洲国产一区在线观看| 精品对白一区国产伦|