合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

        CS 3800 代做、代寫 Python ,java 程序設計

        時間:2024-03-18  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



        CS 3800-Online W. Schnyder
        Spring 2024 3/6/2024
        Homework 7 (due Friday, March 15)
        Instructions: This homework is to be submitted on GradeScope as a single pdf (not in parts) by 11:59 pm on the due date. You may either type your solutions in a word processor and print to a pdf, or write them by hand and submit a scanned copy. Do write and submit your answers as if they were a professional report. There will be point deductions if the submission isn’t neat (is disordered, difficult to read, scanned upside down, etc. . . .).
        Begin by reviewing your class notes, the slides, and the textbook. Then do the exercises below. Show your work. An unjustified answer may receive little or no credit.
        Read: 2.3 (for Tuesday) and 3.1 (for Friday)
        1. [8 Points] Pushdown. For each of the following languages over the alphabet {a, b}, draw the state diagram of a pushdown automaton that accepts this language. For full credit, your automaton should have as few states as possible. (Below, assume that m, n ≥ 0).
        (a) {anbm | n ≤ m}. (b) {anbm | n ≥ m}.
        2. [6 Points] Pushdown. Construct a pushdown automaton P such that (assume m, n ≥ 0): L(P)={ambn |n=2m}
        Specify the components of your automaton and draw a state-diagram. For full credit, your automaton should have as few states as possible.
        3. [6 Points] Pushdown. Construct a pushdown automaton P such that (assume m, n ≥ 0): L(P)={ambn |m≤n≤2m}
        Specify the components of your automaton and draw a state-diagram. For full credit, your automaton should have as few states as possible.
        4. [15 Points] Intersection. Consider the language (n and m are natural numbers ≥ 0) L={anbm |n>mandniseven}
        Clearly L = Lcf l ∩ Lreg where
        Lcfl ={anbm |n>m}andLreg ={w∈{a,b}∗ |whasanevennumberofa’s}
        (a) Draw the state diagram of a DFA for Lreg. For full credit, your automaton should have as few states as possible.
         Page 1 of 3

        CS 3800-Online HW 7 Spring 2024
        (b) Draw the state diagram of a PDA for Lcfl. For full credit, your automaton should
        have as few states as possible.
        (c) Apply the algorithm from class (lecture 15d) to construct a PDA for L. Draw the state diagram of your automaton. (Do not delete useless states, this problem only asks you to demonstrate your understanding of the algorithm.)
        5. [8 Points] Closure properties. In this problem, you are not allowed to construct gram- mars or automata. Everything can be shown using closure properties. Throughout, the reference alphabet is Σ = {a,b} and N denotes the natural numbers (including 0); and n, m ∈ N.
        (a) In Problem 1, you showed that the languages
        {anbm |n≤m} and {anbm |n≥m}
        are context-free. Use this fact to give very simple proofs that {anbm |n<m} and {anbm |n>m}
        are context-free.
        (b) Prove that the language
        {a,b}∗ −{anbn |n∈N}
        6. [6 Points] Closure Properties. Suppose that L is context-free and R is regular.
        (a) Is L − R necessarily context-free? Justify your answer. (b) Is R − L necessarily context free? Justify your answer.
        7. [5 Points] Pumping Lemma. Prove the following variant of the Pumping Lemma:
        For each context-free language L there exists a pumping length p ≥ 0 such that each word
        w with w ∈ L and |w| ≥ p can be written as w=uvxyz
        such that
        i. |vxy|≤p ii. v̸=ε
        iii. uvnxynz∈Lforalln≥0
        Your proof should be simple and succint. References to problem 2.37 in the textbook will not be accepted.
        is context-free.
        Page 2 of 3

        CS 3800-Online HW 7 Spring 2024
        8. [9 Points] Pumping Lemma. This problem leads you step-by-step through a Pumping Lemma based proof (the next problems will not indicate the steps). You will show that the language
        L={anb2nck |n>k≥0}
        (a) Suppose (for contradiction) that L is context free. Then it has a pumping length
        is not context free.
        p≥1. Whyisp≥1?
        (b) Every word w ∈ L with length |w| ≥ p can be written as w = uvxyz with three properties. What are these three properties?
        Select the word w = apb2pcp−1
        (c) Derive a contradiction in case v begins with a. (d) Derive a contradiction in case v begins with b. (e) Derive a contradiction in case v begins with c.
        (f) Use problem 7 to explain that the above proof is complete.
        9. [8 Points] Pumping Lemma. In this problem, you will show that the language
        L = {www | w ∈ {a,b,c}∗}
        (a) Use the pumping Lemma to show that the language {anbanbanb | n ≥ 1} is not
        is not context-free. context free.
        (b) Use closure properties of CFLs to conclude that L is not context-free. (Don’t give a direct proof.)
        10. [0 Point] Do not submit. Exercise 2.6(ac) page 155. The solution is in the book page 160, this is for practice only.
        11. [0 Point] Do not submit. Exercise 2.7(ad) page 155. The solution is in the book pages 160, this is for practice only.
        12. [0 Point] Do not submit. Exercise 2.8 page 155. The solution is in the book page 161, this is for practice only.
        13. [0 Point] Do not submit. Problem 2.18 page 156. The solution was covered in lecture and is also in the book page 161, this is for practice only.
        請加QQ:99515681  郵箱:99515681@qq.com   WX:codehelp 

        掃一掃在手機打開當前頁
      1. 上一篇:代做RISC-V、代寫 C++編程語言
      2. 下一篇:代寫CS5002、代做 java 設計程序
      3. 無相關信息
        合肥生活資訊

        合肥圖文信息
        出評 開團工具
        出評 開團工具
        挖掘機濾芯提升發動機性能
        挖掘機濾芯提升發動機性能
        戴納斯帝壁掛爐全國售后服務電話24小時官網400(全國服務熱線)
        戴納斯帝壁掛爐全國售后服務電話24小時官網
        菲斯曼壁掛爐全國統一400售后維修服務電話24小時服務熱線
        菲斯曼壁掛爐全國統一400售后維修服務電話2
        美的熱水器售后服務技術咨詢電話全國24小時客服熱線
        美的熱水器售后服務技術咨詢電話全國24小時
        海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
        海信羅馬假日洗衣機亮相AWE 復古美學與現代
        合肥機場巴士4號線
        合肥機場巴士4號線
        合肥機場巴士3號線
        合肥機場巴士3號線
      4. 上海廠房出租 短信驗證碼 酒店vi設計

        主站蜘蛛池模板: 国产在线一区二区综合免费视频| 亚洲av无一区二区三区| 91视频国产一区| 视频一区视频二区在线观看| 丰满爆乳一区二区三区| 日本一区二区高清不卡| 国产激情一区二区三区小说| 亚洲国产精品综合一区在线| 日本成人一区二区三区| 国产一区二区三区夜色| 一区国严二区亚洲三区| 人妻体内射精一区二区| 激情爆乳一区二区三区| 国产成人一区二区精品非洲| 中文乱码人妻系列一区二区| 精品人妻码一区二区三区| 天堂资源中文最新版在线一区| 国产色情一区二区三区在线播放| 91麻豆精品国产自产在线观看一区| 人妻体内射精一区二区| 国产一区玩具在线观看| 精品国产日产一区二区三区| 精品一区二区三区中文字幕| 国产一区二区三区在线2021| 久久国产一区二区三区| 99久久精品国产一区二区成人 | 国产aⅴ精品一区二区三区久久 | 日本一区二区三区在线观看| 国产综合无码一区二区辣椒| 日本在线一区二区| 亚洲一区二区三区无码国产| 狠狠色综合一区二区| 天天综合色一区二区三区| 国产精品亚洲一区二区三区久久 | 亚洲AV网一区二区三区| 国产一区二区三区在线免费 | 四虎在线观看一区二区| 欧洲精品码一区二区三区免费看 | 亚洲一区二区影院| 一本一道波多野结衣一区| 国产高清视频一区二区|